document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200105>Question 200105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Continuously Compounded Interest:\r<BR>\n" );
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document.write( "How much would $900 invested at 6% interest compounded continuously be worth after 4 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150477 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much would $900 invested at 6% interest compounded continuously be worth after 4 years?<BR>\n" );
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document.write( "The continuous interest formula: A = P * e^rt<BR>\n" );
document.write( "Where<BR>\n" );
document.write( "P = amt invested<BR>\n" );
document.write( "r = interest rate (in decimal form)<BR>\n" );
document.write( "t = time in yrs<BR>\n" );
document.write( "A = resulting amt<BR>\n" );
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document.write( "A = 900 * e^(.06*4)<BR>\n" );
document.write( "A = 900 * e^.24<BR>\n" );
document.write( "Find e^.24 with a calc<BR>\n" );
document.write( "A = 900 * 1.27125<BR>\n" );
document.write( "A = $1144.12 </SPAN>\n" );
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