document.write( "Question 200169: if you have a bag with 7-red marbles and 6-green marbles and pull out two marbles what is the probability that they will both be red?
\n" ); document.write( "what would be the probability if you placed the first marble into the bag before drawing the second? \n" ); document.write( "

Algebra.Com's Answer #150471 by vleith(2983) $\"\"$ $\"About$

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You start with 13 marbles; 7 red, 6 green
\n" ); document.write( "You pull out on marble. What is the probability of being red? 7/13
\n" ); document.write( "Now you have 12 marbles left; 6 red, 6 green
\n" ); document.write( "Pull out another marble. What is the probability of being red? 6/12\r
\n" ); document.write( "\n" ); document.write( "What is the probability of both being red? $\"+%287%2F13%29+%2A+%286%2F12%29\"$ You can simplify it. \r
\n" ); document.write( "\n" ); document.write( "What if you put the original red one back before drawing a second time?
\n" ); document.write( "Both draws would have the same probability --> 7/13\r
\n" ); document.write( "\n" ); document.write( "So if you drew one marble, then put it back and drew a second time, the probability of both being red are
\n" ); document.write( " $\"%287%2F13%29+%2A+%287%2F13%29\"$ \r
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