document.write( "Question 200154: The path of a falling object is given by the function where vo represents the initial velocity in ft/sec and so represents the initial height in feet.
\n" ); document.write( "A)If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information.
\n" ); document.write( "B)How high is the rock after 1 sec?
\n" ); document.write( "C)After how many seconds will the graph reach maximum height?
\n" ); document.write( "D)What is the maximum height?
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Algebra.Com's Answer #150470 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
\"s=+-16t%5E2%2Bvo%2At%2Bso\"
\n" ); document.write( "a) \"s%28t%29+=+-16t%5E2+%2B+64t+%2B+25\"
\n" ); document.write( "b) \"s%281%29+=+-16%281%29%5E2+%2B+64%2A1+%2B+25\"
\n" ); document.write( "\"s%281%29+=+-16+%2B+64+%2B+25\"
\n" ); document.write( "\"s%281%29+=++73\"
\n" ); document.write( "c) Find the time when the rock is again at 25 feet.
\n" ); document.write( "\"25=+-16t%5E2+%2B+64t+%2B+25\"
\n" ); document.write( "\"0+=+-16t%28t-4%29\"
\n" ); document.write( "So the two values are t=0 and t=4. That is, the rock is at 25 feet high when you first throw it. It arches upward and has arced up and back down to 25 feet at t=4.
\n" ); document.write( "Since the path is a parabola, the midpoint is at t=2
\n" ); document.write( "d)\"s%282%29+=+-16%282%29%5E2+%2B+64%2A2+%2B+25\"
\n" ); document.write( "\"s%282%29+=+-64+%2B+128+%2B+25\"
\n" ); document.write( "\"s%28s%29+=+89\"\r
\n" ); document.write( "\n" ); document.write( "\"graph%28400%2C400%2C+-1%2C+9%2C+-10%2C90%2C+-16x%5E2%2B64x%2B25%29\"
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