document.write( "Question 200135: I got this one wrong:\r
\n" ); document.write( "\n" ); document.write( "A couple plan to have exactly four children. \r
\n" ); document.write( "\n" ); document.write( "(a) Construct a tree diagram and list the sample space.
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Algebra.Com's Answer #150448 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)\r
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\n" ); document.write( "\n" ); document.write( "Using the tree, we get the sample space:\r
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\n" ); document.write( "\n" ); document.write( "{b,b,b,b}
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\n" ); document.write( "{b,b,g,b}
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\n" ); document.write( "\n" ); document.write( "{g,b,b,b}
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\n" ); document.write( "\n" ); document.write( "So for instance {b,g,g,b} means that the couple had a boy, girl, girl, and then a boy (in that order).\r
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\n" ); document.write( "\n" ); document.write( "Note: recall, the sample space is the set of ALL possible outcomes.\r
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\n" ); document.write( "\n" ); document.write( "Since we want to know the chances of the couple having \"at least three boys\", this means they want to know the chances of having 3 boys OR 4 boys (since at least means that figure or more).\r
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\n" ); document.write( "\n" ); document.write( "Looking back at the list of all possible outcomes (ie the sample space) from part a), we see that we have the combinations for 3 boys:\r
\n" ); document.write( "\n" ); document.write( "{b,b,b,g}, {b,b,g,b}, {b,g,b,b}, and {g,b,b,b}\r
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\n" ); document.write( "\n" ); document.write( "So there are 4 cases where the couple would have 3 boys. \r
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\n" ); document.write( "\n" ); document.write( "Also, since there is only ONE way to have 4 boys (of a total of 4 children), this means that
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\n" ); document.write( "\n" ); document.write( "Now simply add the two probabilities to find the chances of either one occurring:\r
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\n" ); document.write( "\n" ); document.write( "So the probability of the couple having AT LEAST 3 boys is \"5%2F16\" which is 0.3125 in decimal form which gives a 31.25% chance.
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