document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=200061>Question 200061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> add and subtract the following fractions.<BR>\n" );
document.write( "2/3+5/7<BR>\n" );
document.write( "3/4+7/12<BR>\n" );
document.write( "4/9-1/8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150440 by </B><A HREF=/tutors/aboutme.mpl?userid=jerrybassmasta><B>jerrybassmasta(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jerrybassmasta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Adding and subtracting fractions are very simple, that is if yo know only one rule.<BR>\n" );
document.write( "The rule is to have common denominators.\r<BR>\n" );
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document.write( "2/3+5/7<BR>\n" );
document.write( "The common denominator for 3 and 7 will be 21. The easiest way is to just multiply them together. <BR>\n" );
document.write( "So you have 21, then you ask yourself. How many times did 3 go into 21. (7 times) So you multiply 2 by 7 as well. Same for the other side. How many times does, 7 go into 21. (3 times) So you  multiply 5 by 3.\r<BR>\n" );
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document.write( "Now you have.<BR>\n" );
document.write( "14/21+15/21     Now you can add them as normal numbers. (Remember you don't add the denominators)\r<BR>\n" );
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document.write( "29/21<BR>\n" );
document.write( "Reducing them are quite simple as well, all you do as subtract the top number from the bottom number.<BR>\n" );
document.write( "1 and 8/21\r<BR>\n" );
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document.write( "3/4+7/12\r<BR>\n" );
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document.write( "Using the same steps you should start off with.<BR>\n" );
document.write( "9/12+7/12<BR>\n" );
document.write( "16/12<BR>\n" );
document.write( "1 and 4/12 You can also simply simplify it to.....<BR>\n" );
document.write( "1 and 1/3\r<BR>\n" );
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document.write( "4/9-1/8<BR>\n" );
document.write( "32/72-9/72<BR>\n" );
document.write( "21/72<BR>\n" );
document.write( "7/24 </SPAN>\n" );
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