document.write( "Question 200086: A search plan has a cruising speed of 250 mph and carries enough fuel for at most 5 hrs of flying. If there is a wind that averages 30 mph and the direction of search is with the wind one way and against it the other, how far can the plane travel before it has to turn back? \n" ); document.write( "
Algebra.Com's Answer #150421 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A search plane has a cruising speed of 250 mph and carries enough fuel for at \n" ); document.write( " most 5 hrs of flying. \n" ); document.write( "If there is a wind that averages 30 mph and the direction of search is with the \n" ); document.write( " wind one way and against it the other, how far can the plane travel before it \n" ); document.write( " has to turn back? \n" ); document.write( ": \n" ); document.write( "Let d = one way distance \n" ); document.write( ": \n" ); document.write( "250+30 = 280; speed with the wind \n" ); document.write( "250=30 = 220; speed against the wind \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "out time + return time = 5 hrs \n" ); document.write( " \n" ); document.write( "Multiply equation by 3080 (LCD) to let rid of the denominators \n" ); document.write( "11d + 14d = 5(3080) \n" ); document.write( "25d = 15400 \n" ); document.write( "d = \n" ); document.write( "d = 616 miles then it has to turn back \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation, find the times \n" ); document.write( " \n" ); document.write( "2.2 + 2.8 = 5 hrs \n" ); document.write( " \n" ); document.write( " |