document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27665>Question 27665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find each of the following squares.\r<BR>\n" );
document.write( "\n" );
document.write( "(w - 1/4)^2\r<BR>\n" );
document.write( "\n" );
document.write( "please help.\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15041 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (w - 1/4)^2<BR>\n" );
document.write( "= (w)^2 + 2(w)(-1/4)+ (-1/4)^2  <BR>\n" );
document.write( "using (a+b)^2 = a^2 + 2ab + b^2 and here a = w and b = (-1/4)<BR>\n" );
document.write( "=  w^2-w/2+ 1/16  [using 2X(-1/4)=(-2/4)=-1/2 and (-1/4)^2=(-1/4)X(-1/4)=(1/16)<BR>\n" );
document.write( "Answer: w^2-w/2+ 1/16  <BR>\n" );
document.write( "Note: You may directly use the formula (x-y)^2 = x^2-2xy + y^2 instead of putting the second term b above as b =(-1/4) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );