document.write( "Question 200005: a farmer has 500m of fencing to build a rectangular enclosure along a river.No fencing is needed along the riverbank.what would be the maximum area enclosed by the fence?what would be the equation? \n" ); document.write( "
Algebra.Com's Answer #150409 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! a farmer has 500m of fencing to build a rectangular enclosure along a river.No fencing is needed along the riverbank.what would be the maximum area enclosed by the fence?what would be the equation? \n" ); document.write( "------------------------ \n" ); document.write( "Area = length*width \n" ); document.write( "2 sides are the width, one is length \n" ); document.write( "500 = l + 2w --> l = 500-2w \n" ); document.write( "Area = l*w \n" ); document.write( "Sub for w \n" ); document.write( "A = w*(500-2w) \n" ); document.write( "A = 500w - 2w^2 ***** That's the equation \n" ); document.write( "------------------ \n" ); document.write( "Method 1 \n" ); document.write( "Set the 1st derivate to zero \n" ); document.write( "0 = 500 - 4w \n" ); document.write( "w = 125 \n" ); document.write( "l = 250 \n" ); document.write( "-------- \n" ); document.write( "Method 2: \n" ); document.write( "A = 500w - 2w^2 \n" ); document.write( "2w^2 - 500w + A = 0 \n" ); document.write( "This is a parabola. The max is at the vertex. \n" ); document.write( "The vertex is at w = -b/2a \n" ); document.write( "w = -b/2a = 500/4 \n" ); document.write( "w = 125 \n" ); document.write( "l = 250 \n" ); document.write( "same as above. \n" ); document.write( "------------ \n" ); document.write( "Area = 125*250 = 31,250 sq meters. \n" ); document.write( " \n" ); document.write( " |