document.write( "Question 200032: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 mph and train B is traveling at 44 mph. Train A passes a station at 5:10 PM. If train B passes the same stations at 5:40 PM, what time will train B catch up with train A? \n" ); document.write( "
Algebra.Com's Answer #150398 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. \n" ); document.write( " Train A is traveling at 40 mph and train B is traveling at 44 mph. \n" ); document.write( " Train A passes a station at 5:10 PM. \n" ); document.write( " If train B passes the same stations at 5:40 PM, what time will train B catch up with train A \n" ); document.write( ": \n" ); document.write( "When train A passes the station, train B is .5 hrs from the station \n" ); document.write( "At 44 mph, we can say; .5*44 = 22 mi is B's dist from Train A at 5:10 \n" ); document.write( ": \n" ); document.write( "Let t = time from 5:10 that train B catches train A \n" ); document.write( ": \n" ); document.write( "Write a distance equation; (train B has to travel 22 mi further than train A) \n" ); document.write( "44t = 40t + 22 \n" ); document.write( ": \n" ); document.write( "44t - 40t = 22 \n" ); document.write( ": \n" ); document.write( "4t = 22 \n" ); document.write( "t = \n" ); document.write( "t = 5.5 hrs for Train B to catch Train A \n" ); document.write( "; \n" ); document.write( "The time: \n" ); document.write( "5:10 + 5:30 = 10:40 PM \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distance traveled by each \n" ); document.write( "Train B = 44 * 5.5 = 242 mi \n" ); document.write( "Train A = 40 * 5.5 = 220 mi \n" ); document.write( "--------------------------- \n" ); document.write( "difference in dist: = 22 mi \n" ); document.write( " |