document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27635>Question 27635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation of a line that contains the given the given point and is parallel to the given line.\r<BR>\n" );
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document.write( "1.)  (6,-2)  3x + 2y = 8<BR>\n" );
document.write( "2.)  (-1,7)  6x - 3y = 9<BR>\n" );
document.write( "3.)  (0,1)   y = 3/7x - 8\r<BR>\n" );
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document.write( "Write an equation of a line that contains the given the given point and is perpendicular to the given line.\r<BR>\n" );
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document.write( "1.)  (6,5)  y = -1/2x + 1<BR>\n" );
document.write( "2.)  (9,-3) y = 3x + 8<BR>\n" );
document.write( "3.)  (0,4)  y = -5/7x - 2\r<BR>\n" );
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document.write( "I'm desperate for some help!!!^^Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15039 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING EXAMPLES WHICH ARE SAME AS YOURS AND TRY.IF STILL IN DIFFICULTY COME BACK..<BR>\n" );
document.write( "Write an equation of a line that contains the given the given point and is parallel to the given line.\r<BR>\n" );
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document.write( "1.)  (6,-2)  3x + 2y = 8<BR>\n" );
document.write( "PARALLEL LINES HAVE EQUAL SLOPES.<BR>\n" );
document.write( "SO PARALLEL LINE TO 3X+2Y=8 IS <BR>\n" );
document.write( "3X+2Y=K....IT IS PASSING THROUGH (6,-2)..SO<BR>\n" );
document.write( "3*6+2*-2=K=18-4=14<BR>\n" );
document.write( "SO EQN.OF THE LINE IS <BR>\n" );
document.write( "3X+2Y=14<BR>\n" );
document.write( "THE OTHER PROBLEMS ARE SIMILAR<BR>\n" );
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document.write( "1. Write in slope intercept the equation of theline passing through the two points.Show that the line is perpindicular to the given line.<BR>\n" );
document.write( "(-2,-2), (1,3); y= 3x-1<BR>\n" );
document.write( "EQN.OF LINE JOINING (X1,Y1) AND (X2,Y2) IS GIVEN BY <BR>\n" );
document.write( "Y-Y1=(X-X1)*(Y2-Y1)/(X2-X1), WHERE (Y2-Y1)/(X2-X1) IS THE SLOPE OF THE LINE AND Y1-X1*(Y2-Y1)/(X2-X1)IS THE INTERCEPT.<BR>\n" );
document.write( "HENCE EQN.OF LINE IS <BR>\n" );
document.write( "Y+2=(X+2)*(3+2)/(1+2)=X(5/3)+2*5/3<BR>\n" );
document.write( "Y=X(5/3)+10/3-2=X(5/3)+4/3.....HENCE SLOPE IS 5/3 AND INTERCEPT IS 4/3<BR>\n" );
document.write( "SLOPE OF GIVEN LINE Y=3X-1 IS 3 ,,,FOR 2 LINES TO BE PERPENDICULAR,THE PRODUCT OF THEIR SLOPES SHOULD BE -1.HERE THE PRODUCT IS 3*5/3=5..HENCE THEY ARE NOT PERPENDICULAR TO EACH OTHER..CHECK BACK YOUR NUMBERS...COPY THE PROBLEM PROPERLY.AS GIVEN THE LINES ARE NOT PERPENDICULAR. <BR>\n" );
document.write( "2. write in slope-intercept form the equation of the line passing through the given point and perpindicular to the given line.<BR>\n" );
document.write( "(-4,-7), y=-4x-7<BR>\n" );
document.write( "SLOPE OF Y=-4X-7 IS -4<BR>\n" );
document.write( "AS GIVEN ABOVE FOR 2 LINES TO BE PERPENDICULAR,THE PRODUCT OF THEIR SLOPES SHOULD BE -1.HENCE THE SLOPE OF THE REQUIRED LINE IS -1/-4=1/4<BR>\n" );
document.write( "EQN.OF REQD. LINE IS <BR>\n" );
document.write( "Y+7=(1/4)(X+4)=X/4 + 1<BR>\n" );
document.write( "Y= X/4 - 6 <BR>\n" );
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