document.write( "Question 200001: I need help with on factoring this one. 2x2+5x-12
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Algebra.Com's Answer #150358 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"2x%5E2%2B5x-12\", we can see that the first coefficient is \"2\", the second coefficient is \"5\", and the last term is \"-12\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"2\" by the last term \"-12\" to get \"%282%29%28-12%29=-24\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-24\" (the previous product) and add to the second coefficient \"5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-24\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-24\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,8,12,24\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-8,-12,-24\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-24\".\r
\n" ); document.write( "\n" ); document.write( "1*(-24)
\n" ); document.write( "2*(-12)
\n" ); document.write( "3*(-8)
\n" ); document.write( "4*(-6)
\n" ); document.write( "(-1)*(24)
\n" ); document.write( "(-2)*(12)
\n" ); document.write( "(-3)*(8)
\n" ); document.write( "(-4)*(6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"5\":\r
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First NumberSecond NumberSum
1-241+(-24)=-23
2-122+(-12)=-10
3-83+(-8)=-5
4-64+(-6)=-2
-124-1+24=23
-212-2+12=10
-38-3+8=5
-46-4+6=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-3\" and \"8\" add to \"5\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-3\" and \"8\" both multiply to \"-24\" and add to \"5\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"5x\" with \"-3x%2B8x\". Remember, \"-3\" and \"8\" add to \"5\". So this shows us that \"-3x%2B8x=5x\".\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2Bhighlight%28-3x%2B8x%29-12\" Replace the second term \"5x\" with \"-3x%2B8x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%5E2-3x%29%2B%288x-12%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x-3%29%2B%288x-12%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x-3%29%2B4%282x-3%29\" Factor out \"4\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%282x-3%29\" Combine like terms. Or factor out the common term \"2x-3\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B5x-12\" factors to \"%28x%2B4%29%282x-3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing \"%28x%2B4%29%282x-3%29\" to get \"2x%5E2%2B5x-12\" or by graphing the original expression and the answer (the two graphs should be identical).
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