document.write( "Question 199938: The width of a rectangle is 1 ft less than the length. The area is 2ft squared. Find the width and lenght. \n" ); document.write( "
Algebra.Com's Answer #150305 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Area =Length * Width = 2 ft^2 \n" ); document.write( ". \n" ); document.write( "but w = L-1 \n" ); document.write( ". \n" ); document.write( "L * ( L-1) = 2 \n" ); document.write( ". \n" ); document.write( "L^2 -L -2 = 0 \n" ); document.write( ". \n" ); document.write( "( L -2) (L+1) =0 \n" ); document.write( ". \n" ); document.write( "L-2 =0,,,,L=2,,,,and w=L-1 = 1,,,ok \n" ); document.write( ". \n" ); document.write( "or L+1 =0,,,,,L=-1,,,,which is not reasonable \n" ); document.write( ". \n" ); document.write( "check \n" ); document.write( ". \n" ); document.write( "Area = L*W = 2*1 =2 ,,,,ok \n" ); document.write( " |