document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199940>Question 199940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student opens a book to two facing pages. The product of the page numbers is 1806, find the pages numbers.<BR>\n" );
document.write( "First page__________<BR>\n" );
document.write( "Second page_________\r<BR>\n" );
document.write( "\n" );
document.write( "How do I work this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150304 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A student opens a book to two facing pages. The product of the page numbers is 1806, find the pages numbers.<BR>\n" );
document.write( "First page__________<BR>\n" );
document.write( "Second page_________ <BR>\n" );
document.write( "How do I work this problem?<BR>\n" );
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document.write( "The quickest and easiest way is to find the sqrt(1806)<BR>\n" );
document.write( "= ~ 42.49<BR>\n" );
document.write( "That's between the 2 numbers, so they're 42 and 43.<BR>\n" );
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document.write( "The hard way:<BR>\n" );
document.write( "n*(n+1) = 1806<BR>\n" );
document.write( "n^2 + n - 1806 = 0<BR>\n" );
document.write( "(n-42)*(n+43) = 0<BR>\n" );
document.write( "n = 42<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );