document.write( "Question 199866: the width of a rectangle is 15 feet less than its length, and the perimeter is 210 feet. find the width. \n" ); document.write( "
Algebra.Com's Answer #150271 by checkley77(12844)\"\" \"About 
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W=L-15
\n" ); document.write( "2W+2L=210
\n" ); document.write( "2(L-15)+2L=210
\n" ); document.write( "2L-30+2L=210
\n" ); document.write( "4L=210+30
\n" ); document.write( "4L=240
\n" ); document.write( "L=240/4
\n" ); document.write( "L=60 ANS. FOR THE LENGTH.
\n" ); document.write( "W=60-15=45 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*45+2*60=210
\n" ); document.write( "90+120=210
\n" ); document.write( "210=210
\n" ); document.write( "
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