document.write( "Question 199866: the width of a rectangle is 15 feet less than its length, and the perimeter is 210 feet. find the width. \n" ); document.write( "
Algebra.Com's Answer #150271 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=L-15 \n" ); document.write( "2W+2L=210 \n" ); document.write( "2(L-15)+2L=210 \n" ); document.write( "2L-30+2L=210 \n" ); document.write( "4L=210+30 \n" ); document.write( "4L=240 \n" ); document.write( "L=240/4 \n" ); document.write( "L=60 ANS. FOR THE LENGTH. \n" ); document.write( "W=60-15=45 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*45+2*60=210 \n" ); document.write( "90+120=210 \n" ); document.write( "210=210 \n" ); document.write( " |