document.write( "Question 199857: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 2:25 A.M.. If train B passes the same station at 2:40 A.M. at what time will train B catch up to train A?\r
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Algebra.Com's Answer #150247 by ankor@dixie-net.com(22740)\"\" \"About 
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Train A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour.
\n" ); document.write( " Train A passes a station at 2:25 A.M.. If train B passes the same station at
\n" ); document.write( " 2:40 A.M. at what time will train B catch up to train A?\r
\n" ); document.write( "\n" ); document.write( "When will train B catch up to train A?
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\n" ); document.write( "Find the distance that train B is behind train A at 2:25
\n" ); document.write( "Train B is 15 min (which is.25 hr), from train A at that time.
\n" ); document.write( "120 * .25 = 30 mi
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\n" ); document.write( "Relative speed between the two trains: 120 - 100 = 20 mph
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\n" ); document.write( "How long will it take to cover 30 mi at 20 mph?
\n" ); document.write( "Time = \"30%2F20\" = 1.5 hrs
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\n" ); document.write( "Train B catches Train A: 2:25 + 1:30 = 3:55 AM
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\n" ); document.write( "Check solution by finding the distance traveled by each train in 1.5 hrs:
\n" ); document.write( "120 * 1.5 = 180 mi
\n" ); document.write( "100 * 1.5 = 150 mi
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\n" ); document.write( "difference = 30 mi
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\n" ); document.write( "Did all this make sense to you?
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