document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199838>Question 199838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 + sqrt 3x - 2 = -5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150218 by </B><A HREF=/tutors/aboutme.mpl?userid=jerrybassmasta><B>jerrybassmasta(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jerrybassmasta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 + sqrt 3x - 2 = -5\r<BR>\n" );
document.write( "\n" );
document.write( "To solve this is pretty simple if you get the square root.<BR>\n" );
document.write( "First ask yourself, what is the opposite of a square root?<BR>\n" );
document.write( "If you know that you can solve the problem easily. <BR>\n" );
document.write( "You have to square it.\r<BR>\n" );
document.write( "\n" );
document.write( "3 + sqrt 3x - 2 = -5<BR>\n" );
document.write( "becomes\r<BR>\n" );
document.write( "\n" );
document.write( "3+3x-2=-5^2<BR>\n" );
document.write( "Following PEMDAS, you have to solve the exponent first.\r<BR>\n" );
document.write( "\n" );
document.write( "3+3x-2=25\r<BR>\n" );
document.write( "\n" );
document.write( "Add 2 on the other side and then subtract 3.\r<BR>\n" );
document.write( "\n" );
document.write( "3x=24\r<BR>\n" );
document.write( "\n" );
document.write( "Now divide.\r<BR>\n" );
document.write( "\n" );
document.write( "x=8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );