document.write( "Question 199681This question is from textbook Beginning Algebra
\n" ); document.write( ": i need to solve this using the substitution method\r
\n" ); document.write( "\n" ); document.write( " 8x+2y-7=0
\n" ); document.write( "-2x-1y+2=0
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Algebra.Com's Answer #150203 by Mathtut(3670)\"\" \"About 
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8x+2y-7=0........................eq 1
\n" ); document.write( "-2x-1y+2=0---->y=-2x+2...........eq 2
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\n" ); document.write( "take y's value from eq 2 and substitute it into eq 1
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\n" ); document.write( "8x+2(-2x+2)-7=0
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\n" ); document.write( "8x-4x+4-7=0
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\n" ); document.write( "4x=3
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\n" ); document.write( "x=3/4
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\n" ); document.write( "y=-2(3/4)+2=1/2
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