document.write( "Question 199745: if n is a natural number such that n=p1 power a1 *p2 power a2*p3 power a3..............*pk power ak and pk are distinct primes , then show that log n>=k log2 \n" ); document.write( "
Algebra.Com's Answer #150190 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! n= p(1)^a(1) + p(2)^a(2) + p(3)^a(3) + .........+ p(k)^a(k) \n" ); document.write( ". \n" ); document.write( "n is a natural number,,,this leads to n=1 or larger integer. ,,,, AND it limits each term of the sequence to a positive number. That is, the p\"s cannot be + or -, as this would restrict the terms to an even number, to make n positive, which was not stated. \n" ); document.write( ". \n" ); document.write( "Likewise, the \"a\" values cannot be negative, leading to a fraction, or a fraction, which would lead to not whole numbers. \n" ); document.write( ". \n" ); document.write( "The given that p(k) is a distinct prime, leads to the min value of p(k) being the min prime, or 2 .,,,or larger,,, (1 is a special number, not prime) \n" ); document.write( ". \n" ); document.write( "n = something positive * a number 2 or larger raised to a positive number( making it >2) \n" ); document.write( ". \n" ); document.write( "n>2^ k \n" ); document.write( ". \n" ); document.write( "and taking log of both sides \n" ); document.write( ". \n" ); document.write( "log n > log 2^k or log n > k log 2 \n" ); document.write( " |