document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199746>Question 199746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> area of a sale. The area of in square meters for a triangular sale is given by A(x)=x^2+5x+6 Find A(5), if the hignt of the sail is x+3 meters, then what is the lenght of the sail?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150170 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "I'm unsure how to measure the area of a 'sale'.  Perhaps it is the area of the floor surface in a store where a sale is being held.  However, I suspect you meant 'sail' since that is the word you used later in the problem, and I will proceed on that assumption.  Furthermore, I have no idea what the 'hignt' or 'lenght' of a sail (or a sale for that matter) is.  I'm going out on a limb here and will assume you meant 'height' and 'length'.  The point of this part of my lesson is that if I am going to take the time to help you, you are obligated to take the time to communicate correctly and completely.  Enough said about that.\r<BR>\n" );
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document.write( "If\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ A(x) = x^2 + 5x + 6\">\r<BR>\n" );
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document.write( "Then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ A(5) =(5)^2 + 5(5) + 6\">\r<BR>\n" );
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document.write( "The arithmetic is left as an exercise for the student.\r<BR>\n" );
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document.write( "The area of a triangle is given by:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ A = \frac{bh}{2}\">\r<BR>\n" );
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document.write( "Therefore, the measure of the base (your length), given the area and the height, is given by:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ b = \frac{2A}{h}\">\r<BR>\n" );
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document.write( "Since the area as a function of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\"> is the function <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large A(x) \">, the measure of the base, which is equivalent to the length that is the answer to this problem can be determined by:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ b = \frac{2(x^2 + 5x + 6)}{x + 3}\">\r<BR>\n" );
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document.write( "There are two ways to proceed from here.  One, you could use polynomial long division to obtain the quotient <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{x^2 + 5x + 6}{x + 3}\">.  The other way, and much simpler, is to simply factor the polynomial in the numerator:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ b = \frac{2(x + 2)(x + 3)}{x + 3}\">\r<BR>\n" );
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document.write( "Then eliminate the factor common to both numerator and denominator:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ b = 2(x + 2) = 2x + 4\">\r<BR>\n" );
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document.write( "Done.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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