document.write( "Question 199782: Hello!\r
\n" ); document.write( "\n" ); document.write( "Find a polynomial with integer coefficients and a leading coefficient of one that satisfies the given conditions.\r
\n" ); document.write( "\n" ); document.write( "P has degree 2, and zeros 1 + i and 1 - i. \r
\n" ); document.write( "\n" ); document.write( "thanks for the homework help!
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Algebra.Com's Answer #150165 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x=1%2Bi\" or \"x=1-i\" Start with the given zeros\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=i\" or \"x-1=-i\" Get the constants to the left side\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2=%28i%29%5E2\" or \"%28x-1%29%5E2=%28-i%29%5E2\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2=-1\" or \"%28x-1%29%5E2=-1\" Square i and -i to get -1\r
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\n" ); document.write( "\n" ); document.write( "Since the equations are the same, we can focus on the first equation \"%28x-1%29%5E2=-1\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1=-1\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1%2B1=0\" Add 1 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B2=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the polynomial \"f%28x%29=x%5E2-2x%2B2\" has zeros of 1+i and 1-i\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "You can check the answer with the quadratic formula.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"x%5E2-2x%2B2\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=-2\", and \"C=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%282%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=-2\", and \"C=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%282%29+%29%29%2F%282%281%29%29\" Negate \"-2\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4-4%281%29%282%29+%29%29%2F%282%281%29%29\" Square \"-2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4-8+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%282%29\" to get \"8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+-4+%29%29%2F%282%281%29%29\" Subtract \"8\" from \"4\" to get \"-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+-4+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+2%2Ai%29%2F%282%29\" Take the square root of \"-4\" to get \"2%2Ai\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B+2%2Ai%29%2F%282%29\" or \"x+=+%282+-+2%2Ai%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282%29%2F%282%29+%2B+%282%2Ai%29%2F%282%29\" or \"x+=++%282%29%2F%282%29+-+%282%2Ai%29%2F%282%29\" Break up the fraction for each case. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1%2Bi\" or \"x+=++1-i\" Reduce. \r
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\n" ); document.write( "\n" ); document.write( "So the zeros are \"x+=+1%2Bi\" or \"x+=+1-i\" which confirms our answer.
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