document.write( "Question 195874: all numbers undefined for 2/4x+5
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document.write( "Divide and Simplify 5/t divided by 10/t
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document.write( "Subtract and simplify 13/d-8 - 13/8-d
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document.write( "add and simplify 7/15r + 4/9r \n" );
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Algebra.Com's Answer #150156 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! all numbers undefined for 2/4x+5 \n" ); document.write( "Is that a question? \n" ); document.write( "------------------- \n" ); document.write( "Divide and Simplify 5/t divided by 10/t \n" ); document.write( "Multiply extremes and means - NUM = extremes = 5t \n" ); document.write( "DEN = means = 10t \n" ); document.write( "5t/10 = 1/2 \n" ); document.write( "----------- \n" ); document.write( "Subtract and simplify 13/d-8 - 13/8-d \n" ); document.write( "(d-8) = -(8-d) \n" ); document.write( "--> 13/(d-8) + 13/(d-8) \n" ); document.write( "= 26/(d-8) \n" ); document.write( "Use parentheses. That could be (13/d) - 8 - (13/8) - d, an entirely different problem. \n" ); document.write( "----------------- \n" ); document.write( "add and simplify 7/15r + 4/9r \n" ); document.write( "In class, they harp on the LCD for this type of problem, finding it, using it, etc. \n" ); document.write( "You can multiply to the 2 DENs and use that, it will always work. You have to reduce the results, anyway. \r \n" ); document.write( "\n" ); document.write( "Don't waste time on a test finding the LEAST common denominator, just find A common denominator (unless the problem asks for the LCD). \n" ); document.write( "7/15r + 4/9r \n" ); document.write( "Common DEN = 135r (no need to use r^2) \n" ); document.write( "=63/135r + 60/135r \n" ); document.write( "= 123/135r \n" ); document.write( "= 41/45r\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |