document.write( "Question 199771: Hello and Thank You for your help.\r
\n" ); document.write( "\n" ); document.write( "I know the answewr to my problem is 10 years. I kept subtracting to get the answer. I don't know how to write an equation to solve the problem. The question is\r
\n" ); document.write( "\n" ); document.write( "Bill will put aside $100 per month this year for retiremenmt. Next year he will put away $200 per month the third year $300 per month. Each year will increase by $100 per month. How many years will Bill save to reach $66,000?
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Algebra.Com's Answer #150139 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You basically have the sequence:
\n" ); document.write( "12*100,
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\n" ); document.write( "\n" ); document.write( "note: I'm multiplying by 12 since he deposits money 12 times a year.\r
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\n" ); document.write( "\n" ); document.write( "and you're adding up the terms to get:
\n" ); document.write( "12*100+12*200=12*300,
\n" ); document.write( "12*100+12*200+12*300=12*600,
\n" ); document.write( "12*100+12*200+12*300+12*400=12*1000,
\n" ); document.write( "12*100+12*200+12*300+12*400+12*500=12*1500, ...\r
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\n" ); document.write( "\n" ); document.write( "and you want to know which partial sum will be equal to 66,000. \r
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\n" ); document.write( "\n" ); document.write( "So you basically want to know when 12*100+12*200+12*300+12*400+12*500+...=66000\r
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\n" ); document.write( "\n" ); document.write( "We can factor out the GCF 12*100 to get: 12*100(1+2+3+4+5+....)=66000\r
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\n" ); document.write( "\n" ); document.write( "and we're left with a very familiar series in the parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "It turns out that (this is a well known formula).\r
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\n" ); document.write( "\n" ); document.write( "So the equation then becomes: \"12%2A100%28%28n%28n%2B1%29%29%2F2%29=66000\"\r
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\n" ); document.write( "\n" ); document.write( "where \"n\" is the number of years.\r
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\n" ); document.write( "\n" ); document.write( "\"12%2A100%28%28n%28n%2B1%29%29%2F2%29=66000\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"100%28%28n%28n%2B1%29%29%2F2%29=66000%2F12\" Divide both sides by 12.\r
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\n" ); document.write( "\n" ); document.write( "\"100%28%28n%28n%2B1%29%29%2F2%29=5500\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"100%28n%28n%2B1%29%29%2F2=5500%2F100\" Divide both sides by 100.\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%28n%2B1%29%29%2F2=55\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"n%28n%2B1%29=55%2A2\" Multiply both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "\"n%28n%2B1%29=110\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2Bn=110\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2Bn-110=0\" Subtract 110 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"An%5E2%2BBn%2BC\" where \"A=1\", \"B=1\", and \"C=-110\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"n\":\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-%281%29+%2B-+sqrt%28+%281%29%5E2-4%281%29%28-110%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=1\", and \"C=-110\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B-+sqrt%28+1-4%281%29%28-110%29+%29%29%2F%282%281%29%29\" Square \"1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B-+sqrt%28+1--440+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-110%29\" to get \"-440\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B-+sqrt%28+1%2B440+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%281--440%29\" as \"sqrt%281%2B440%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B-+sqrt%28+441+%29%29%2F%282%281%29%29\" Add \"1\" to \"440\" to get \"441\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B-+sqrt%28+441+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B-+21%29%2F%282%29\" Take the square root of \"441\" to get \"21\". \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-1+%2B+21%29%2F%282%29\" or \"n+=+%28-1+-+21%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%2820%29%2F%282%29\" or \"n+=++%28-22%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+10\" or \"n+=+-11\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible solutions are \"n+=+10\" or \"n+=+-11\" \r
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\n" ); document.write( "\n" ); document.write( "Recall that the value of \"n\" is the number of years. Since you cannot have a negative year, this excludes \"n+=+-11\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"n+=+10\" which means that it will take 10 years to save up to $66,000.\r
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\n" ); document.write( "\n" ); document.write( "If you have any questions, email me at jim_thompson5910@hotmail.com
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