document.write( "Question 27596: If Lynn can type a page in p minutes, what piece of the page can she do in 5 minutes? \r
\n" ); document.write( "\n" ); document.write( "so the ratio would be 1:p = ?:5
\n" ); document.write( "that's where I go fuzzy.
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Algebra.Com's Answer #15010 by askmemath(368)\"\" \"About 
You can put this solution on YOUR website!
An easy way of doing these types of problems is by giving some value to p
\n" ); document.write( "for e.g. if p = 10
\n" ); document.write( "Then Lynn takes 10minutes to type 1 page
\n" ); document.write( "which means that in 5 minutes i.e. half the time she will type half the page
\n" ); document.write( "or 5/10 of the page
\n" ); document.write( "Now if in place of 10 i had p
\n" ); document.write( "then she would type 5/p of the page :-)\r
\n" ); document.write( "\n" ); document.write( "OR
\n" ); document.write( "if you've gotten till 1:p = ?:5
\n" ); document.write( "Then Remember \"Product of Means = Product of Extremes\"
\n" ); document.write( "or P*? = 1*5
\n" ); document.write( "Dividing by P on both sides
\n" ); document.write( "? = (1*5)/P Which is what we've got as above!!! :-)
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