document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199652>Question 199652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <ABC and <PQR are supplementary angles and <ABC is eleven times as large as <PQR. Determine the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150089 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorvolunteer><B>tutorvolunteer(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorvolunteer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's use variables in solving:  <ABC = x , < PQR = y\r<BR>\n" );
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document.write( "Since x and y are supplementary, x+y = 180 by the definition of supplementary angles.\r<BR>\n" );
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document.write( "Also, x is 11 times as large as y, so x = 11y.\r<BR>\n" );
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document.write( "Now we have 2 equations with 2 variables and can solve using a variety of methods for systems of equations (i.e. substitution, multiplication with addition, etc)\r<BR>\n" );
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document.write( "Plug in x=11y to  x+y=180, so 12y = 180, and y = 15. Using this, we find that x = 165. </SPAN>\n" );
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