document.write( "Question 199662: Given f(x)=(ax)/(x^2+b), a≠0, b≠0. Find a and b such that f’(1)=0 and f’(0)=2. \n" ); document.write( "

Algebra.Com's Answer #150086 by edjones(8007) $\"\"$ $\"About$

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Given f(x)=(ax)/(x^2+b), a≠0, b≠0. Find a and b such that f’(1)=0 and f’(0)=2.
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\n" ); document.write( "when f(1)=0
\n" ); document.write( "a/(1+b)=0
\n" ); document.write( "a=(1+b)*0
\n" ); document.write( "a=0
\n" ); document.write( "b=any real number except -1 because division by zero is not allowed.
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\n" ); document.write( "when f(0)=2
\n" ); document.write( "(a*0)/(0+b)=2
\n" ); document.write( "The equation cannot equal 2 it can only equal zero with any a or b.
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\n" ); document.write( "Ed \n" ); document.write( "

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