document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199685>Question 199685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From a group of 6 men and 4 women, a committee of 3 is to be selected at random. find Probability of at least 2 women to be selected for the committee.\r<BR>\n" );
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document.write( "Please list the equation with the formula below, I don't understand how to work the other explanation\r<BR>\n" );
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document.write( "P(at least 2 women) = P(2 women) + P(3 women) \r<BR>\n" );
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document.write( "Thank you!  this probability is really hard to understand, thanks for your help :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150072 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the number of 3 person committees from a group of 10 is 10C3\r<BR>\n" );
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document.write( "groups of 2 women from a field of 4 is 4C2<BR>\n" );
document.write( "groups of 1 men from a field of 6 is 6C1<BR>\n" );
document.write( "so the number of 3 person groups with 2 women is (4C2)(6C1)\r<BR>\n" );
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document.write( "groups of 3 women from a field of 4 is 4C3\r<BR>\n" );
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document.write( "so the probability of at least 2 women in the group is [(4C2)(6C1) + 4C3] / 10C3 </SPAN>\n" );
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