document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199648>Question 199648</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Please help me (!) <BR>\n" );
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document.write( "   Solve for x: ((log b, 36)) - ((log b, 2)) = ((log b, x))\r<BR>\n" );
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document.write( "     \"b\" is the base...thanks!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #150037 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=150037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">    Solve for x: ((log b, 36)) - ((log b, 2)) = ((log b, x))<BR>\n" );
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document.write( "Subtraction can be replaced by division with logs giving:<BR>\n" );
document.write( "LOGb(36/2) = LOGb(x)<BR>\n" );
document.write( "LOGb(18) = LOGb(x)<BR>\n" );
document.write( "18 = x<BR>\n" );
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