document.write( "Question 199481: Paddling for 4 hrs with a 6 km/hr current and a return trip against the same current took 10 hr. What is the speed in still water. \n" ); document.write( "

Algebra.Com's Answer #150033 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Paddling for 4 hrs with a 6 km/hr current and a return trip against the same
\n" ); document.write( " current took 10 hr. What is the speed in still water.
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\n" ); document.write( "Let s = speed in still water
\n" ); document.write( "then
\n" ); document.write( "(s+6) = speed downstream
\n" ); document.write( "and
\n" ); document.write( "(s-6) = speed upstream
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\n" ); document.write( "The trip there and the trip back are the same distance, write a Dist equaiton
\n" ); document.write( "Dist = time * speed
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\n" ); document.write( "10(s-6) = 4(s+6)
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\n" ); document.write( "10s - 60 = 4s + 24
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\n" ); document.write( "10s - 4s = 24 + 60
\n" ); document.write( "6s = 84
\n" ); document.write( "s = $\"84%2F6\"$
\n" ); document.write( "s = 14 km/hr
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\n" ); document.write( "Check solution by finding the dist
\n" ); document.write( "10(8) = 80 km
\n" ); document.write( "4(20) = 80 km \n" ); document.write( "

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