document.write( "Question 199624: 10k gold ----------------42%
\n" ); document.write( "14k gold ----------------58%
\n" ); document.write( "18k gold ----------------75%
\n" ); document.write( "22k gold ----------------92%
\n" ); document.write( "24k gold ----------------100%\r
\n" ); document.write( "\n" ); document.write( "How many grams of 22k gold must be mixed with 5 grams of 14k gold to produce 18k gold?
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Algebra.Com's Answer #150022 by ankor@dixie-net.com(22740)\"\" \"About 
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10k gold ----------------42%
\n" ); document.write( "14k gold ----------------58%
\n" ); document.write( "18k gold ----------------75%
\n" ); document.write( "22k gold ----------------92%
\n" ); document.write( "24k gold ----------------100%
\n" ); document.write( "How many grams of 22k gold must be mixed with 5 grams of 14k gold to produce 18k gold?
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\n" ); document.write( " translate k to decimal equiv of per cent.
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\n" ); document.write( "Let x = amt of 92% (22k) required
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\n" ); document.write( ".92x + .58(5) = .75(x+5)
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\n" ); document.write( ".92x + 2.9 = .75x + 3.75
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\n" ); document.write( ".92x - .75x = 3.75 - 2.9
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\n" ); document.write( ".17x = .85
\n" ); document.write( "x = \".85%2F.17\"
\n" ); document.write( "x = 5 grams of 22k required
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