document.write( "Question 199624: 10k gold ----------------42%
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document.write( "14k gold ----------------58%
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document.write( "18k gold ----------------75%
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document.write( "22k gold ----------------92%
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document.write( "24k gold ----------------100%\r
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document.write( "How many grams of 22k gold must be mixed with 5 grams of 14k gold to produce 18k gold?
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Algebra.Com's Answer #150022 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 10k gold ----------------42% \n" ); document.write( "14k gold ----------------58% \n" ); document.write( "18k gold ----------------75% \n" ); document.write( "22k gold ----------------92% \n" ); document.write( "24k gold ----------------100% \n" ); document.write( "How many grams of 22k gold must be mixed with 5 grams of 14k gold to produce 18k gold? \n" ); document.write( ": \n" ); document.write( " translate k to decimal equiv of per cent. \n" ); document.write( ": \n" ); document.write( "Let x = amt of 92% (22k) required \n" ); document.write( ": \n" ); document.write( ".92x + .58(5) = .75(x+5) \n" ); document.write( ": \n" ); document.write( ".92x + 2.9 = .75x + 3.75 \n" ); document.write( ": \n" ); document.write( ".92x - .75x = 3.75 - 2.9 \n" ); document.write( ": \n" ); document.write( ".17x = .85 \n" ); document.write( "x = \n" ); document.write( "x = 5 grams of 22k required \n" ); document.write( " \n" ); document.write( " |