document.write( "Question 199598: I'm not to sure if this is the right section for my question but here goes:
\n" );
document.write( "I'm working on factorizing using the difference of two squares rule and I need help factorizing this expression.
\n" );
document.write( "1) (5x-4)^2 - (x-7)^2 \n" );
document.write( "
Algebra.Com's Answer #149999 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Starting with: \n" ); document.write( "(5x-4)^2 - (x-7)^2 \n" ); document.write( ". \n" ); document.write( "Let a = (5x-4) \n" ); document.write( "and b = (x-7) \n" ); document.write( ". \n" ); document.write( "Now, we can rewrite our original equation as: \n" ); document.write( "a^2 - b^2 \n" ); document.write( "This, we recognize as being equal to: \n" ); document.write( "(a+b)(a-b) \n" ); document.write( ". \n" ); document.write( "Plugging back in our values of 'a' and 'b' we get: \n" ); document.write( "(a+b)(a-b) \n" ); document.write( "= (5x-4 + x-7)(5x-4 - (x-7)) \n" ); document.write( "= (6x-11)(5x-4 - x+7) \n" ); document.write( "= (6x-11)(4x+3) (this is what they're looking for) \n" ); document.write( " \n" ); document.write( " |