document.write( "Question 199598: I'm not to sure if this is the right section for my question but here goes:
\n" ); document.write( "I'm working on factorizing using the difference of two squares rule and I need help factorizing this expression.
\n" ); document.write( "1) (5x-4)^2 - (x-7)^2
\n" ); document.write( "

Algebra.Com's Answer #149999 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Starting with:
\n" ); document.write( "(5x-4)^2 - (x-7)^2
\n" ); document.write( ".
\n" ); document.write( "Let a = (5x-4)
\n" ); document.write( "and b = (x-7)
\n" ); document.write( ".
\n" ); document.write( "Now, we can rewrite our original equation as:
\n" ); document.write( "a^2 - b^2
\n" ); document.write( "This, we recognize as being equal to:
\n" ); document.write( "(a+b)(a-b)
\n" ); document.write( ".
\n" ); document.write( "Plugging back in our values of 'a' and 'b' we get:
\n" ); document.write( "(a+b)(a-b)
\n" ); document.write( "= (5x-4 + x-7)(5x-4 - (x-7))
\n" ); document.write( "= (6x-11)(5x-4 - x+7)
\n" ); document.write( "= (6x-11)(4x+3) (this is what they're looking for)
\n" ); document.write( "
\n" ); document.write( "
\n" );