document.write( "Question 199600: I'm not to sure if this is the right section for my question but here goes:
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document.write( "I'm working on factorizing quadratic trinomials and here is a question I need help with factorizing this expression.
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document.write( "1) 20x^2-44x+21 \n" );
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Algebra.Com's Answer #149996 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! To factor the quadratic, you need to look at the factors for the coefficients of of leading term (20) and the trailing term (21). Then decide which pairs of factors result in a difference of -44 \r \n" ); document.write( "\n" ); document.write( "The factor pairs for 20 are \n" ); document.write( "1,20 \n" ); document.write( "2,10 \n" ); document.write( "4,5 \n" ); document.write( "The factor pairs for 21 are \n" ); document.write( "1,21 \n" ); document.write( "3,7\r \n" ); document.write( "\n" ); document.write( "So now you use those pairs of numbers and try to find sums/difference of products that get you to -44\r \n" ); document.write( "\n" ); document.write( "So let's try 2,10 and 1,21 \n" ); document.write( "Does 2*1 + 10*21 = -44 no \n" ); document.write( "Does 2*21 + 1*10 = - 44 No \n" ); document.write( "OK, let's try something esle \n" ); document.write( "Try 2,10 3,7 \n" ); document.write( "Does 2*7 + 10*3 = -44 No, but it does equal 44. We are getting closer. All we need to do now is make the signs correct\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is a good URL for checking answers on this type of thing \n" ); document.write( "http://72.3.253.76:8080/webMathematica3/quickmath/page.jsp?s1=algebra&s2=factor&s3=basic \n" ); document.write( " \n" ); document.write( " |