document.write( "Question 199597: I have 500 hectolitres of 4.6% abv (alcohol by volume) beer in a tank. I need to increase the alcohol % up to 5%abv from 4.6%abv the max volume of tank 500hl so we need to remove some of the 4.6% and replace it with 7.15% abv bringing up the abv percentage to 5%. I need to know how much 4.6% to remove and how much 7.15% to replace it with. Can you please show me the formula used to figure out this question please
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document.write( "Mark
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Algebra.Com's Answer #149993 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! I have 500 hectolitres of 4.6% abv (alcohol by volume) beer in a tank. \n" ); document.write( " I need to increase the alcohol % up to 5%abv from 4.6%abv the max volume \n" ); document.write( "of tank 500hl so we need to remove some of the 4.6% and replace it with 7.15% \n" ); document.write( " abv bringing up the abv percentage to 5%. \n" ); document.write( "I need to know how much 4.6% to remove and how much 7.15% to replace it with. \n" ); document.write( ": \n" ); document.write( "Let x = amt to be removed, this is also the amt of 7.15% to be added \n" ); document.write( ": \n" ); document.write( ".046(500 - x) + .0715x = .05(500) \n" ); document.write( ": \n" ); document.write( "All you need now is some basic algebra \n" ); document.write( "Multiply what's inside the brackets \n" ); document.write( "23 - .046x + .0715x = 25 \n" ); document.write( ": \n" ); document.write( ".046x + .0715x = 25 - 23 \n" ); document.write( ": \n" ); document.write( ".0255x = 2 \n" ); document.write( "x = \n" ); document.write( "x = 78.43 hl removed and 78.43 hl of 7.15% added \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if this is true \n" ); document.write( ".046(500 - 78.43) + .0715(78.43) = .05(500) \n" ); document.write( ".046(421.57) + .0715(78.43) = .05(500) \n" ); document.write( "19.39 + 5.61 = 25; confirms our solution \n" ); document.write( " |