document.write( "Question 27537: The greater of two consecutive even integers is 6 less than three times the lesser. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #14998 by yougan aungamuthu(2)\"\" \"About 
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\n" ); document.write( " Basically we are told that the bigger integer is 6 less than 3
\n" ); document.write( " times the smaller integer. this means that when we subtract 6
\n" ); document.write( " from three times the smaller integer we get the bigger integer.
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\n" ); document.write( " Therefore,
\n" ); document.write( " 3(smaller integer) - 6 = bigger integer
\n" ); document.write( "Let us call the first even integer 2k where k can be any integer (the 2 is necessary to emphasise we are dealing with even numbers since any even number must have a factor of 2).\r
\n" ); document.write( "\n" ); document.write( "Since we are dealing with consecutive even integers the bigger number will be 2k+2 (we add 2 since consecutive even numbers differ by 2)\r
\n" ); document.write( "\n" ); document.write( "Now we use 3(smaller integer) - 6 = bigger integer
\n" ); document.write( " 3(2k) - 6 = 2k+2
\n" ); document.write( " 6k-6=2k+2
\n" ); document.write( " 4k=8
\n" ); document.write( " k=2 which means the numbers are 2(2) and 2(2)+2
\n" ); document.write( " i.e 4 and 6
\n" ); document.write( "Note: the first number is 2k but k = 2 therefore the number 2(2)
\n" ); document.write( " the second number is 2k+2 but k=2 therefore the number is 2(2)+2\r
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