document.write( "Question 199561: 2. A business invests $8,000 in a savings account for two years. At the beginning of the second year, an additional $2,500 is invested. At the end of the second year, the account balance is $11,445. What was the annual interest rate? \r
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Algebra.Com's Answer #149978 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"A=P%281%2Br%29\" Start with the interest formula. Note: since we're only concerned with year intervals, this means that \"t=1\" (so we don't have to worry about exponents)\r
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\n" ); document.write( "\n" ); document.write( "\"A=8000%281%2Br%29\" Plug in \"P=8000\" (since $8,000 is the original amount in the account)\r
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\n" ); document.write( "\n" ); document.write( "\"A=8000%2B8000r\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "So after one full year, you now have \"8000%2B8000r\" dollars in the account.\r
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\n" ); document.write( "\n" ); document.write( "Now because \"an additional $2,500 is invested\", this pushes up the amount to \"8000%2B8000r%2B2500\" (just add 2500 to the last expression). Combine like terms to get \"10500%2B8000r\" \r
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\n" ); document.write( "\n" ); document.write( "So the new principal is \"P=10500%2B8000r\"\r
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\n" ); document.write( "\n" ); document.write( "Since after two years you have $11,445, this means that \"A=11445\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Br%29\" Go back to the original formula\r
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\n" ); document.write( "\n" ); document.write( "\"11445=%2810500%2B8000r%29%281%2Br%29\" Plug in \"A=11445\", \"P=10500%2B8000r\" and \"r=1%2Br\"\r
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\n" ); document.write( "\n" ); document.write( "\"11445=10500%2B18500%2Ar%2B8000%2Ar%5E2\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"0=10500%2B18500%2Ar%2B8000%2Ar%5E2-11445\" Subtract 11445 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=8000%2Ar%5E2%2B18500%2Ar-945\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"ar%5E2%2Bbr%2Bc\" where \"a=8000\", \"b=18500\", and \"c=-945\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for r\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( " Plug in \"a=8000\", \"b=18500\", and \"c=-945\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B-+sqrt%28+342250000-4%288000%29%28-945%29+%29%29%2F%282%288000%29%29\" Square \"18500\" to get \"342250000\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B-+sqrt%28+342250000--30240000+%29%29%2F%282%288000%29%29\" Multiply \"4%288000%29%28-945%29\" to get \"-30240000\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B-+sqrt%28+342250000%2B30240000+%29%29%2F%282%288000%29%29\" Rewrite \"sqrt%28342250000--30240000%29\" as \"sqrt%28342250000%2B30240000%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B-+sqrt%28+372490000+%29%29%2F%282%288000%29%29\" Add \"342250000\" to \"30240000\" to get \"372490000\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B-+sqrt%28+372490000+%29%29%2F%2816000%29\" Multiply \"2\" and \"8000\" to get \"16000\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B-+19300%29%2F%2816000%29\" Take the square root of \"372490000\" to get \"19300\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-18500+%2B+19300%29%2F%2816000%29\" or \"r+=+%28-18500+-+19300%29%2F%2816000%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28800%29%2F%2816000%29\" or \"r+=++%28-37800%29%2F%2816000%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+0.05\" or \"r+=+-2.3625\" Divide \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"r+=+0.05\" or \"r+=+-2.3625\"\r
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\n" ); document.write( "However, since you CANNOT have a negative interest rate, this means that the only possible answer is \"r+=+0.05\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply by 100 to get \"100%2A0.05=5\". \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the annual interest rate is 5%
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