document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199565>Question 199565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hose can fill a swimming pool in 18 hours.  Another hose needs 3 more hours to fill the pool than the two hoses combined.  How long would it take the second hose to fill the pool? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149977 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st hose does 1/18 the job in one hr.<BR>\n" );
document.write( "The other hose needs x hours to do the job. So it can do 1/x of the job in one hour.<BR>\n" );
document.write( "1/18 + 1/x = (18+x)/18x amount of the job done in one hr by the 2 hoses combined.<BR>\n" );
document.write( "18x/(x+18) hours it takes for both hoses to fill the pool.<BR>\n" );
document.write( "(18x/(x+18))+3 hours it takes the second hose to fill the pool (3 hrs more than the 2 hoses combined).<BR>\n" );
document.write( "x=(18x/(x+18))+3<BR>\n" );
document.write( "x-3=18x/(x+18)<BR>\n" );
document.write( "(x-3)(x+18)=18x<BR>\n" );
document.write( "x^2+15x-54=18x<BR>\n" );
document.write( "x^2-3x-54=0<BR>\n" );
document.write( "(x-9)(x+6)=0<BR>\n" );
document.write( "x=9 hrs<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );