document.write( "Question 199556: how do i find the length and width of a rectangle if the perimeter is 46 and the area is 42? \n" ); document.write( "
Algebra.Com's Answer #149960 by ankor@dixie-net.com(22740)\"\" \"About 
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How do i find the length and width of a rectangle if the perimeter is 46
\n" ); document.write( " and the area is 42?
\n" ); document.write( ":
\n" ); document.write( "Write perimeter equation:
\n" ); document.write( "2L + 2W = 46
\n" ); document.write( "Simplify, divide by 2:
\n" ); document.write( "L + W = 23
\n" ); document.write( "Arrange for substitution
\n" ); document.write( "W = (23-L)
\n" ); document.write( ":
\n" ); document.write( "Write the area equation:
\n" ); document.write( "L * W = 42
\n" ); document.write( ";
\n" ); document.write( "Substitute (23-L) for W
\n" ); document.write( "L *(23-L) = 42
\n" ); document.write( ":
\n" ); document.write( "-L^2 + 23L - 42 = 0
\n" ); document.write( "Multiply by -1
\n" ); document.write( "L^2 - 23L + 42 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(L - 21)(L - 2) = 0
\n" ); document.write( "The greater solution will be the length
\n" ); document.write( "L = 21, then W = 2
\n" ); document.write( ";
\n" ); document.write( "Length = 21
\n" ); document.write( "Width = 2
\n" ); document.write( ":
\n" ); document.write( "Check solutions by finding the perimeter
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