document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199413>Question 199413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right triangle is 2 ft more than twice the other leg.  The hypotenuse is 1 ft. more than the longer leg.  Find the length of the hypotenuse of the right triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149959 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a=longer leg, b=shorter, c=hypotenuse.<BR>\n" );
document.write( "a=2b+2<BR>\n" );
document.write( "c=a+1<BR>\n" );
document.write( "c=2b+2+1<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "(2b+2)^2+b^2=(2b+3)^2<BR>\n" );
document.write( "4b^2+8b+4+b^2=4b^2+12b+9<BR>\n" );
document.write( "b^2-4b-5=0 Subtract the right side from the left<BR>\n" );
document.write( "(b-5)(b+1)=0<BR>\n" );
document.write( "b=5'<BR>\n" );
document.write( "a=12'<BR>\n" );
document.write( "c=13'<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );