document.write( "Question 199456: A population consists of 15 items, 10 of which are acceptable. In a sample of 4 items, what is the probability that exactly three are acceptable? Assume the samples are drawn without replacement. \n" ); document.write( "
Algebra.Com's Answer #149953 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A population consists of 15 items, 10 of which are acceptable. In a sample of 4 items, what is the probability that exactly three are acceptable? Assume the samples are drawn without replacement. \n" ); document.write( "--------------------- \n" ); document.write( "# of ways to pick 3 \"acceptable\": 10C3 = 120 \n" ); document.write( "# of ways to pick 1 not acceptable: 5C1 = 5 \n" ); document.write( "------------ \n" ); document.write( "# of ways to pick 4 where exactly 3 are acceptable: 120*5 = 600 \n" ); document.write( "# of ways to pick 4 with no restrictions: 15C4 = 1365 \n" ); document.write( "---------- \n" ); document.write( "Probability that you want = 600/1365 = 40/91 \n" ); document.write( "==================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |