document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27578>Question 27578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> L has y-intercept(0,2) and is perpendicular to the line with equation 2x-3y=6. I have a hard time with problems like these. please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14995 by </B><A HREF=/tutors/aboutme.mpl?userid=yougan+aungamuthu><B>yougan aungamuthu(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=yougan+aungamuthu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> STEP 1<BR>\n" );
document.write( "          What is given?<BR>\n" );
document.write( "             * line L with y-intercept (0,2)<BR>\n" );
document.write( "             * line with equation 2x-3y=6 but perpendicular to line L<BR>\n" );
document.write( "STEP 2<BR>\n" );
document.write( "          Draw a diagram\r<BR>\n" );
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document.write( "STEP 3<BR>\n" );
document.write( "          To find the equation of any line you need 2 things, namely, <BR>\n" );
document.write( "          gradient and a point on the line you want to find the equation of.<BR>\n" );
document.write( "STEP 4<BR>\n" );
document.write( "          The point on L is (0,2)<BR>\n" );
document.write( "          The gradient we get from the line 2x-3y=6 since it is perpendicular <BR>\n" );
document.write( "          to L. What do we know about perpendicular lines? Yes, the product <BR>\n" );
document.write( "          of their gradients is -1.<BR>\n" );
document.write( "          What is the gradient of 2x-3y=6? Write 2x-3y=6 in the y-form i.e <BR>\n" );
document.write( "          make y subject of the formula. Thus<BR>\n" );
document.write( "                            2x-3y=6<BR>\n" );
document.write( "                            -3y=6-2x<BR>\n" );
document.write( "                              y=-2+(2/3)x<BR>\n" );
document.write( "                 which means the gradient is 2/3.<BR>\n" );
document.write( "STEP 5<BR>\n" );
document.write( "          since the lines are perpendicular, the product of gradients is -1<BR>\n" );
document.write( "                     (gradient L)(2/3)= -1  therefore <BR>\n" );
document.write( "                        gradient L = -3/2\r<BR>\n" );
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document.write( "Step 6            using the formula for a straight line y=mx+c<BR>\n" );
document.write( "                  we substitute for m, which is the gradient L = -3/2<BR>\n" );
document.write( "                  and c, which is the y-intercept 2 to get the required <BR>\n" );
document.write( "                  equation of L  y = (-3/2)x + 2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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