document.write( "Question 199535: hudson river flows at a rate of 5 miles per hour. a patrol boat travels 40miles upriver, and returns in a total time of 6 hours. what is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #149935 by jim_thompson5910(35256)\"\" \"About 
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Let x = speed of boat in still water
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\n" ); document.write( "\"d=rt\" Start with the distance-rate-time formula
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\n" ); document.write( "\"40=%28x-3%29t\" Plug in \"d=40\" and \"r=x-5\". This equation represents the upstream journey.
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\n" ); document.write( "\n" ); document.write( "\"40%2F%28x-5%29=t\" Divide both sides by \"x-5\" to isolate \"t\";
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\n" ); document.write( "\n" ); document.write( "So the expression for the time it takes to go upstream can be represented by the expression \"40%2F%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Go back to the distance-rate-time formula\r
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\n" ); document.write( "\"40=%28x%2B5%29t\" Plug in \"d=40\" and \"r=x%2B5\". This equation represents the downstream journey
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\n" ); document.write( "\"40%2F%28x%2B5%29=t\" Divide both sides by \"x%2B5\" to isolate \"t\";
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\n" ); document.write( "So the expression for the time it takes to go downstream can be represented by the expression \"40%2F%28x%2B5%29\"
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\n" ); document.write( "\n" ); document.write( "Now simply add the two time expressions to get: \"40%2F%28x-5%29%2B40%2F%28x%2B5%29\"
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\n" ); document.write( "\n" ); document.write( "\"40%2F%28x-5%29%2B40%2F%28x%2B5%29=6\" Now set that expression equal to the total time of 6 hours
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\n" ); document.write( "\"40%28x%2B5%29%2B40%28x-5%29=6%28x%2B5%29%28x-5%29\" Multiply every term by the LCD \"%28x%2B5%29%28x-5%29\" to clear the denominators.
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\n" ); document.write( "\"40%28x%2B5%29%2B40%28x-5%29=6%28x%5E2-25%29\" FOIL
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\n" ); document.write( "\"40x%2B200%2B40x-200=6x%5E2-150\" Distribute
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\n" ); document.write( "\"40x%2B200%2B40x-200-6x%5E2%2B150=0\" Subtract \"6x%5E2\" from both sides. Add \"150\" to both sides.
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\n" ); document.write( "\n" ); document.write( "\"-6x%5E2%2B80x%2B150=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"Ax%5E2%2BBx%2BC\" where \"A=-6\", \"B=80\", and \"C=150\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%2880%29+%2B-+sqrt%28+%2880%29%5E2-4%28-6%29%28150%29+%29%29%2F%282%28-6%29%29\" Plug in \"A=-6\", \"B=80\", and \"C=150\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+6400-4%28-6%29%28150%29+%29%29%2F%282%28-6%29%29\" Square \"80\" to get \"6400\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+6400--3600+%29%29%2F%282%28-6%29%29\" Multiply \"4%28-6%29%28150%29\" to get \"-3600\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+6400%2B3600+%29%29%2F%282%28-6%29%29\" Rewrite \"sqrt%286400--3600%29\" as \"sqrt%286400%2B3600%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+10000+%29%29%2F%282%28-6%29%29\" Add \"6400\" to \"3600\" to get \"10000\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B-+sqrt%28+10000+%29%29%2F%28-12%29\" Multiply \"2\" and \"-6\" to get \"-12\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B-+100%29%2F%28-12%29\" Take the square root of \"10000\" to get \"100\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-80+%2B+100%29%2F%28-12%29\" or \"x+=+%28-80+-+100%29%2F%28-12%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2820%29%2F%28-12%29\" or \"x+=++%28-180%29%2F%28-12%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-5%2F3\" or \"x+=+15\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible solutions are \"x+=+-5%2F3\" or \"x+=+15\" \r
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\n" ); document.write( "\n" ); document.write( "However, you can't have a negative speed. So the only answer is \"x+=+15\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the speed of the boat in still water is 15 mph.
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