document.write( "Question 199508: A 45-foot rope is to be cut into three pieces. The second piece must be twice as long as the first piece and the third peice must be 9 feet longer than 3 times the length of the second piece. How long should each three peices be?\r
\n" ); document.write( "\n" ); document.write( "How do I write this problem algibraicly? How do I solve it? My Final is tomarrow please help.\r
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Algebra.Com's Answer #149905 by Electrified_Levi(103)\"\" \"About 
You can put this solution on YOUR website!
Hi, Hope I can help,
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\n" ); document.write( "A 45-foot rope is to be cut into three pieces. The second piece must be twice as long as the first piece and the third peice must be 9 feet longer than 3 times the length of the second piece. How long should each three peices be?
\n" ); document.write( "How do I write this problem algibraicly? How do I solve it? My Final is tomarrow please help.
\n" ); document.write( "-Andrew
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\n" ); document.write( "So the total amount of rope is 45 ft, so, that means the length of all three rope lengths will equal 45
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\n" ); document.write( "We have to name the lengths in terms of \"x\"
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\n" ); document.write( "You can usually name one of the variables, in this case there are three, \"x\", it probably doesn't matter, but we will use the easiest way
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\n" ); document.write( "We will name Length 1, \"x\"
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\n" ); document.write( "The second piece must be twice as long as the first piece,
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\n" ); document.write( "If the length 1 is \"x\", and length 2 has to be twice as long, length 2 = \"2x\"
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\n" ); document.write( "We will work the third piece a little slower, because it is the hardest of the three
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\n" ); document.write( "the third peice must be 9 feet longer than 3 times the length of the second piece,
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\n" ); document.write( "the third peice must be 9 feet longer than 3 times the length of the second piece, which is \"2x\"
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\n" ); document.write( "the third peice must be 9 feet longer than 3 times \"2x\"
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\n" ); document.write( "the third peice must be 9 feet longer than 3(2x)
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\n" ); document.write( "the third peice must be 9 feet longer than \"6x\",
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\n" ); document.write( "You would now add \"9\" to \"6x\"
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\n" ); document.write( "the third peice must be \"6x + 9\",
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\n" ); document.write( "Length 3 = \"6x + 9\"
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\n" ); document.write( "Length 1 = \"+x+\"
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\n" ); document.write( "Length 2 = \"+2x+\"
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\n" ); document.write( "Length 3 = \"+6x+%2B+9+\"
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\n" ); document.write( "All of these lengths will add up to 45, we can now have our equation
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\n" ); document.write( "\"+%28x%29+%2B+%282x%29+%2B+%286x+%2B+9%29+=+45+\"
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\n" ); document.write( "We can get rid of the parentheses
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\n" ); document.write( "\"+x+%2B+2x+%2B+6x+%2B+9+=+45+\"
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\n" ); document.write( "Now add like terms
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\n" ); document.write( "\"+x+%2B+2x+%2B+6x+%2B+9+=+45+\" = \"+9x+%2B+9+=+45+\"
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\n" ); document.write( "We will move \"9\" to the right side
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\n" ); document.write( "\"+9x+%2B+9+=+45+\" = \"+9x+%2B+9+-+9+=+45+-+9+\" = \"+9x+=+36+\", to find \"x\" divide each side by \"9\"
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\n" ); document.write( "\"+9x+=+36+\" = \"+9x%2F9+=+36%2F9+\" = \"+x+=+4+\", you can check your answer by replacing \"x\" with \"4\" in the equation
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\n" ); document.write( "\"+%28x%29+%2B+%282x%29+%2B+%286x+%2B+9%29+=+45+\" = \"+%284%29+%2B+%282%284%29%29+%2B+%286%284%29+%2B+9%29+=+45+\" = \"+%284%29+%2B+%288%29+%2B+%28+24+%2B+9%29+=+45+\" = \"+%284%29+%2B+%288%29+%2B+%2833%29+=+45+\" = \"+45+=+45+\" ( True )
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\n" ); document.write( "\"+x+=+4+\"
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\n" ); document.write( "Length 1 = \"+x+\" = \"+4+\"
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\n" ); document.write( "Length 2 = \"+2x+\" = \"+2%284%29+\" = \"+8+\"
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\n" ); document.write( "Length 3 = \"+6x+%2B+9+\" = \"+6%284%29+%2B+9+\" = \"+24+%2B+9+\" = \"+33+\"
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\n" ); document.write( "To show you that you can make \"x\" any of the lengths, I will briefly do \"x\" as the Length 2
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\n" ); document.write( "Length 2 = \"+x+\", if length 2 is twice length 1, then length 1 = \"+x%2F2+\"
\n" ); document.write( ", Length 3, is 9 more than three times the second's length, or \"+3x+%2B+9+\"
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\n" ); document.write( "Length 1 = \"+x%2F2+\"
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\n" ); document.write( "Length 2 = \"+x+\"
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\n" ); document.write( "Length 3 = \"+3x+%2B+9+\"
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\n" ); document.write( "You would then add these to equal 45 again
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\n" ); document.write( "\"+%28x%2F2%29+%2B+%28x%29+%2B+%28+3x+%2B+9+%29+=+45+\", you would solve to find \"x\" = 8, which was length 2
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\n" ); document.write( "\"+x+=+8+\"
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\n" ); document.write( "Length 1 = \"+x%2F2+\" = \"+8%2F2+\" = \"+4+\"
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\n" ); document.write( "Length 2 = \"+x+\" = \"+8+\"
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\n" ); document.write( "Length 3 = \"+3x+%2B+9+\" = \"+3%288%29+%2B+9+\" = \"+24+%2B+9+\" = \"+33+\"
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\n" ); document.write( "If you even wanted to have Length 3 = \"x\" you could, but that would be the hardest and most difficult.
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\n" ); document.write( "Length 1 = \"+4+\"
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\n" ); document.write( "Length 2 = \"+8+\"
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\n" ); document.write( "Length 3 = \"+33+\"
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\n" ); document.write( "Hope I helped, Levi
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