document.write( "Question 199508: A 45-foot rope is to be cut into three pieces. The second piece must be twice as long as the first piece and the third peice must be 9 feet longer than 3 times the length of the second piece. How long should each three peices be?\r
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document.write( "How do I write this problem algibraicly? How do I solve it? My Final is tomarrow please help.\r
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document.write( "-Andrew \n" );
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Algebra.Com's Answer #149901 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let x=length of first piece, y=length of second piece, and z=length of third piece\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \"The second piece must be twice as long as the first piece \", this means that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now because these pieces come from a 45 ft rope, they must add back up to 45. So we have the equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So all you need to do is solve |