document.write( "Question 199466: Hi!\r
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document.write( "A quadratic function of f is given.
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document.write( "f (x) = 3x^2 + 6x - 7 \r
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document.write( "Find its vertex and its x- and y-intercept(s)\r
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document.write( "thanks for the homework help! \n" );
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Algebra.Com's Answer #149883 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Manipulate your equation into the \"vertex form\": \n" ); document.write( "y= a(x-h)^2+k \n" ); document.write( "where \n" ); document.write( "(h,k) is the vertex \n" ); document.write( ". \n" ); document.write( "f(x) = 3x^2 + 6x - 7 \n" ); document.write( "f(x) = (3x^2 + 6x) - 7 \n" ); document.write( "f(x) = 3(x^2 + 2x) - 7 \n" ); document.write( "Complete the square: \n" ); document.write( "f(x) = 3(x^2 + 2x + 1) - 7 - 3 \n" ); document.write( "f(x) = 3(x+1)^2 - 10 \n" ); document.write( ". \n" ); document.write( "Therefore, the vertex is: \n" ); document.write( "(h,k) = (-1, -10) \n" ); document.write( ". \n" ); document.write( "To find the y-intercepts, set x=0 and solve for f(x): \n" ); document.write( "f(x) = 3x^2 + 6x - 7 \n" ); document.write( "f(x) = 3(0^2) + 6(0) - 7 \n" ); document.write( "f(x) = - 7 \n" ); document.write( "y-intercept is (0, -7) \n" ); document.write( ". \n" ); document.write( "To find x-intercepts, set f(x)=0 and solve for x: \n" ); document.write( "0 = 3x^2 + 6x - 7 \n" ); document.write( "Using the quadratic equation, we get: \n" ); document.write( "x = {0.826, -2.826} \n" ); document.write( "x-intercepts are at: \n" ); document.write( "(-2.826,0) and (0.826,0) \n" ); document.write( ". \n" ); document.write( "Details of quadratic follows: \n" ); document.write( "
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