document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199357>Question 199357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle 36m.  The width is 18 yd less than twice the length.  Find the length and width of the rectangle.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149882 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=2L<BR>\n" );
document.write( "P=2W+2L<BR>\n" );
document.write( "36=2(2L)+2L<BR>\n" );
document.write( "36=4L+2L<BR>\n" );
document.write( "36=6L<BR>\n" );
document.write( "L=36/6<BR>\n" );
document.write( "L=6 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "W=2*6=12 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "pROOF:<BR>\n" );
document.write( "36=2*12+2^6<BR>\n" );
document.write( "36=24+12<BR>\n" );
document.write( "36=36 </SPAN>\n" );
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