document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199435>Question 199435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the length of a rectangle is 3 inches longer than the width and that the perimeter of the rectangle is 78. \r<BR>\n" );
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document.write( "a) set up an equation involving only w, the width of the rectangle. \r<BR>\n" );
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document.write( "b) solve this equation algebraically to find the length of the rectangle. Find the width as well. Use the appropriate units of measure in your answers. \r<BR>\n" );
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document.write( "Length_____, Width______ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149875 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+3<BR>\n" );
document.write( "2L+2W=78<BR>\n" );
document.write( "2(W+3)+2W=78<BR>\n" );
document.write( "2W+6+2W=78<BR>\n" );
document.write( "4W=78-6<BR>\n" );
document.write( "4W=72<BR>\n" );
document.write( "W=72/4<BR>\n" );
document.write( "W=18 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=18+3=21 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "pROOF:<BR>\n" );
document.write( "2*21+2*18=78<BR>\n" );
document.write( "42+36=78<BR>\n" );
document.write( "78=78 </SPAN>\n" );
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