document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27542>Question 27542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the formula for finding the perimeter of a circle? And the perimeter of a semi-circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14987 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the formula for finding the perimeter of a circle? And the perimeter of a semi-circle?\r<BR>\n" );
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document.write( "The formula for the perimeter or the circumference of a circle is (Pi times d) or (Pi times (2r)) = 2(Pi)r = 2 X (22/7) X r where r is the radius of the circle.And   d is the diameter of the circle equal to twice the radius r <BR>\n" );
document.write( "that is d=2r<BR>\n" );
document.write( "Thus the formula for the perimeter of a circle is (22d/7) or (44r/7)  where d is diameter and r the radius of the circle.<BR>\n" );
document.write( "And the perimeter of a semi circle is [(Pi)times radius] = half of the perimeter of the circle <BR>\n" );
document.write( "So formula for the perimeter of a semi circle is(11d/7) or (22r/7) </SPAN>\n" );
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