document.write( "Question 199400: Solve \"abs%285x-3%29%3E=12\" \n" ); document.write( "
Algebra.Com's Answer #149833 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Alan's solution is incorrect!
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document.write( "Rules for removing absolute value bars:\r\n" );
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document.write( "1. For cases of \"abs%28EXPRESSION%29%3CA\" where \"A\" is positive:\r\n" );
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document.write( "Rewrite as\r\n" );
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document.write( "\"-A%3CEXPRESSION%3CA\" \r\n" );
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document.write( "2. For cases of \"abs%28EXPRESSION%29%3C=A\"\r\n" );
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document.write( "Rewrite as\r\n" );
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document.write( "\"-A%3CEXPRESSION%3C=A\" \r\n" );
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document.write( "3. For cases of \"abs%28EXPRESSION%29%3EA\" where \"A\" is positive:\r\n" );
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document.write( "Rewrite as\r\n" );
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document.write( "\"EXPRESSION%3C-A\" OR \"EXPRESSION%3EA\"\r\n" );
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document.write( "4. For cases of \"abs%28EXPRESSION%29%3E=A\"\r\n" );
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document.write( "Rewrite as\r\n" );
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document.write( "\"EXPRESSION%3C=-A\" OR \"EXPRESSION%3E=A\"\r\n" );
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document.write( "\"abs%285x-3%29%3E=12\"\r\n" );
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document.write( "This is case 4, so to remove the absolute value\r\n" );
document.write( "bars:\r\n" );
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document.write( "\"abs%285x-3%29%3E=12\"\r\n" );
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document.write( "Rewrte that as\r\n" );
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document.write( "\"5x-3%3C=-12\" OR \"5x-3%3E=12\"\r\n" );
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document.write( "Solve each\r\n" );
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document.write( "\"5x%3C=-9\" OR \"5x%3E=15\"\r\n" );
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document.write( "\"x%3C=-9%2F5\" OR \"x%3E=3\"\r\n" );
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document.write( "\"x%3C=-1%264%2F5\" OR \"x%3E=3\"\r\n" );
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document.write( "Mark the points \"-1%264%2F5\" and \"3\" on the number line.\r\n" );
document.write( "Notice that to plot \"-1%264%2F5\" you mark a point \"4%2F5\"\r\n" );
document.write( "of the way between \"-1\" and \"-2\" \r\n" );
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document.write( "We mark them with solid circles because the problem has \"%22%22%3C=%22%22\"\r\n" );
document.write( "and/or \"%22%22%3E=%22%22\".  If it had been just \"%22%22%3C%22%22\" and/or \"%22%22%3E%22%22\"\r\n" );
document.write( "you would have left the circles open\r\n" );
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document.write( " ------------@-----------------------@----------\r\n" );
document.write( " -4   -3   -2   -1    0    1    2    3    4    5   \r\n" );
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document.write( "For the \"x%3C=-1%264%2F5\" part we shade left of \"-1%264%2F5\"\r\n" );
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document.write( "<============@-----------------------@----------\r\n" );
document.write( " -4   -3   -2   -1    0    1    2    3    4    5\r\n" );
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document.write( "And since the solution is that OR \"x%3E=3\" we shade\r\n" );
document.write( "right of \"3\":\r\n" );
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document.write( "<============@-----------------------@===========>\r\n" );
document.write( " -4   -3   -2   -1    0    1    2    3    4    5\r\n" );
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document.write( "Now for the interval notation, the left shaded part is\r\n" );
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document.write( "(\"-infinity\",-\"-1%264%2F5\"]\r\n" );
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document.write( "and we union that with the right shaded part [3,oo)\r\n" );
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document.write( "and the final answer in interval notation is\r\n" );
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document.write( "        (\"-infinity\",\"-1%264%2F5\"] U [3,\"infinity\")\r\n" );
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document.write( "Edwin
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