document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=199294>Question 199294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove that 7^(n+2)-35(7^n-1)/44(7^n+2) is equal to 1/49 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #149806 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=149806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [ 7^(n+2) -35*7^9n-1)] / [ 44(7^(n+2) ) ] = 1/49<BR>\n" );
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document.write( "[ 1-35*7^-3] / 44 = 1/49<BR>\n" );
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document.write( "[ 1 - 35 / (49*7) ] / 44 = 1/49<BR>\n" );
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document.write( "[ 1-5/49] / 44 = 1/49<BR>\n" );
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document.write( "[49/49 -5/49 ] / 44 = 1/49<BR>\n" );
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document.write( "[ 44 / 49 ] / 44 = 1/49<BR>\n" );
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document.write( "(44/49) * (1/44) = 1/49 = 1/49,,,,,,ok </SPAN>\n" );
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