document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27530>Question 27530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of any line perpendicular to the line through points(0,5) and <BR>\n" );
document.write( "(-3,-4) I started with y=0(x)+ 5, y=-3x-4 i am not sure what to do next. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14980 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the slope of any line perpendicular to the line through points(0,5) and <BR>\n" );
document.write( "(-3,-4) I started with y=0(x)+ 5, y=-3x-4 i am not sure what to do next.<BR>\n" );
document.write( "THAT IS NOT THE WAY FIRST FIND SLOPE OF THE LINE JOINING THE 2 POINTS ..IT IS..(Y2-Y1)/(X2-X1)=(5+4)/(0+3)=9/3=3<BR>\n" );
document.write( "NOW SLOPE OF THE PERPENDICULAR LINE = -1/3<BR>\n" );
document.write( "RULE FOR PERPENDICULAR LINES =PRODUCT OF SLOPES = -1  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );