document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27548>Question 27548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me write the slope-intercept form of the line that passes through the given point and is perpendicular to the graph of each equasion.<BR>\n" );
document.write( "(-3,-2),y=x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14977 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me write the slope-intercept form of the line that passes through the given point and is perpendicular to the graph of each equasion.<BR>\n" );
document.write( "(-3,-2),y=x+2<BR>\n" );
document.write( "EQN.OF LINE PERPENDICULAR TO THE ABOVE IS OF THE FORM <BR>\n" );
document.write( "Y = -X + K<BR>\n" );
document.write( "IT IS PASSING THROUGH (-3,-2)..SO..<BR>\n" );
document.write( "-2=-(-3)+K=K+3<BR>\n" );
document.write( "K=-2-3=-5..HENCE EQN. OF REQUIRED LINE IS<BR>\n" );
document.write( "Y = -X - 5 <BR>\n" );
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